\[\begin{bmatrix}2s+3t\\r+s-2t\\4r+s\\3r-s-t\end{bmatrix}=r\begin{bmatrix}0\\1\\4\\3\end{bmatrix}+s\begin{bmatrix}2\\1\\1\\-1\end{bmatrix}+t\begin{bmatrix}3\\-2\\0\\-1 \end{bmatrix}=\begin{bmatrix}0&2&3\\1&1&-2\\4&1&0\\3&-1&-1 \end{bmatrix}\begin{bmatrix}r\\ s\\ t \end{bmatrix}\]

where r, s and t are any real numbers. So the set is Col A where

\[A=\begin{bmatrix}0&2&3\\1 & 1&-2\\4&1&0\\3&-1&-1 \end{bmatrix}\]

Result:

\[A=\begin{bmatrix}0&2&3\\1 & 1&-2\\4&1&0\\3&-1&-1 \end{bmatrix}\]