# Consider the non-right triangle below. 19610800151.jpg Suppose that m\angle CAB=61^{\circ}, and that

Consider the non-right triangle below.

Suppose that $$\displaystyle{m}\angle{C}{A}{B}={61}^{{\circ}}$$, and that $$\displaystyle{x}={35}{c}{m}$$ and $$\displaystyle{y}={15}{c}{m}$$. What is the area of this triangle?

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Onlaceing
Step 1
Given triangle

Step 2
find area
$$\displaystyle{A}={\frac{{{1}}}{{{2}}}}{x}\cdot{y}\cdot{\sin{{\left({A}\right)}}}$$
$$\displaystyle={\frac{{{1}}}{{{2}}}}\cdot{35}\cdot{15}\cdot{\sin{{\left({61}\right)}}}$$
$$\displaystyle={229.58767}{c}{m}^{{{2}}}$$
Round off answer as per requirement.