On a frictionless, horizontal air table, puck A (with mass 0.250 kg) is moving t

vakirnarhh

vakirnarhh

Answered question

2021-11-18

Puck A (with mass 0.250 kg) is travelling toward puck B (with mass 0.350 kg), which is originally at rest, on a frictionless, horizontal air table. Puck A has a velocity to the left of 0.120 m/s after the contact, while puck B has a velocity to the right of 0.650 m/s.
(a) How fast was puck A traveling before to the collision?
(b) Determine the change in the system's overall kinetic energy that results from the impact.

Answer & Explanation

pseudoenergy34

pseudoenergy34

Beginner2021-11-19Added 22 answers

The masses of pucks A and B are  mA=0.250kg and mB=0.350kg respectively.

Using right as the constructive axis, we have:vA1=??? vA2=0.120m/s vB1=0 vB2=0.650m/s

We are aware that a system's overall momentum is the vector sum of the moments of each of the system's constituent particles: p=pA+pB+ ... (1)

Where a particel's momenta are determined by: p=mv (2)

Additionally, we know that a system's momentum is conserved for an isolated system, hence p= constant.

a) The system (pucks A and B) is regarded as an isolated system because the table is frictionless. In accordance with the principle of momentum conservation, the system's momentum before and after the collision are equal, leading to the following results: p1=22 (3)

Applying equation (1) and (3), we get: pA1

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