Find the derivative with respect to the independent variable. f(x)=9\cos x-2\sin

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sklicatias 2021-11-21 Answered

Find the derivative with respect to the independent variable.

f (x) = 9 \cos x - 2 \sin x

f'(x)=

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romancemrf

Answered 2021-11-22 Author has 14 answers

Step 1
We have to find derivatives of function:

f (x) = 9 \cos x - 2 \sin x

We know the derivatives of trigonometric ratios:

\frac{d \cos x}{d x} = - \sin x

\frac{d \sin x}{d x} = \cos x

Step 2
So differentiating the function

f (x) = 9 \cos x - 2 \sin x

with respect to 'x', we get

f (x) = 9 \cos x - 2 \sin x

f^{'} (x) = 9 \frac{d \cos x}{d x} - 2 \frac{d \sin x}{d x}

= 9 (- \sin x) - 2 (\cos x)

= - 9 \sin - 2 \cos x

Hence, value of

f^{'} (x) i s - 9 \sin - 2 \cos x

.

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