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We have given: limx→0+xx2 By the exponent rule ax=eln(ax)=exlna limx→0+xx2=limx→0+ex2ln(x) By the chain rule, limx−>0+xx2=limx→0+ex2⋅x limx→0+xx2=limx→0+ex2+2x2ex2 limx→0+xx2=e0+0 limx→0+xx2=1+0 limx→0+xx2=1 Result: 1
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