Find the limits. lim_{xrightarrow3sqrt2}(frac{x}{2}-frac{1}{x})

Tyra 2021-02-11 Answered
Find the limits. limx32(x21x)
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broliY
Answered 2021-02-12 Author has 97 answers
We have the given expression of limit as
f(x)=limx32(x21x)
Put the value of x in the above expression we get:
f(x)=322132=32132
on simplification of above step we get:
f(x)=9132=832=423
f(x)=423
We get a fixed value as constant. Therefore, limit exist at the given point.
Hence,the value of limit f(x)=limx32(x21x) is (423)
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