Find all real solutions of the equation. 25x^{2}+70x+49=0

vadulgattp 2021-11-16 Answered
Find all real solutions of the equation.
25x2+70x+49=0
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Expert Answer

George Spencer
Answered 2021-11-17 Author has 12 answers

Step 1
The given equation is,
25x2+70x+49=0
If a quadratic equation is given in the standard form as ax2+bx+c=0,a0, then the solutions of the equation is given as,
x=b±b24ac2a
Step 2
On comparing the given quadratic equation with the standard form of the quadratic equation, we get
x=70±(702)4(25)(49)225
=70±4900490050
=7050
=75
Therefore, the solution of the given equation is 75

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Witionsion
Answered 2021-11-18 Author has 19 answers
Step 1: Use the formula for the roots of the quadratic equation
x=b±b24ac2a
In the standard form, determine a, b and c from the original equation and insert them into the formula for the roots of the quadratic equation.
25x2+70x+49=0
a=25
b=70
c=49
x=70±70242549225
Step 2: Raise to the degree
x=70±490042549225
Step 3: Multiply the numbers
x=70±49004900225
Step 4: Subtract the numbers
x=70±0225
Step 5: Calculate the square root
x=70±0225
Step 6: Add zero
x=70225
Step 7: Multiply the numbers
x=7050
Step 8: Reduce the same terms in the numerator and denominator
x=75
The solution
x=75
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