Solve quadratic equation. 9x^{2}+6x+1=0

Jason Watson 2021-11-21 Answered
Solve quadratic equation.
9x2+6x+1=0
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Expert Answer

Mespirst
Answered 2021-11-22 Author has 17 answers
Step 1
Consider the given equation.
9x2+6x+1=0
Now, find the factor of the equation.
9x2+6x+1=0
9x2+3x+3x+1=0
3x(3x+1)+1(3x+1)=0
(3x+1)2=0
Step 2
Further simplify.
(3x+1)=0
3x=-1
x=13
Therefore, the solution of the equation is x=13.
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Mespirst
Answered 2021-11-23 Author has 17 answers
Step 1: Use the formula for the roots of the quadratic equation
x=b±b24ac2a
In the standard form, determine a, b and c from the original equation and insert them into the formula for the roots of the quadratic equation.
9x2+6x+1=0
a=9
b=6
c=1
x=6±6249129
Step 2: Raise to the degree
x=6±3649129
x=6±3649129
Step 3: Multiply the numbers
x=6±3649129
x=6±363629
Step 4: Subtract the numbers
x=6±363629
x=6±029
Step 5: Calculate the square root
x=6±029
x=6±029
Step 6: Add zero
x=6±029
x=629
Step 7: Multiply the numbers
x=629
x=618
Step 8: Reduce the same terms in the numerator and denominator
x=618
x=13
The solution
x=13
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