Solve the equation. \log(57x)=2+\log(x-2)

dictetzqh

dictetzqh

Answered question

2021-11-16

Solve the equation.
log(57x)=2+log(x2)

Answer & Explanation

Sevensis1977

Sevensis1977

Beginner2021-11-17Added 15 answers

Given,
log(57x)=2+log(x2)
Step 2
On simplification, we get
log(57x)log(x2)=2
log(57xx2)=2   [logmlogn=log(mn)]
57xx2=102   [logx=yx=10y]
57xx2=100
57x=100(x2)
57x=100x200
43x=200
x=20043

Mespirst

Mespirst

Beginner2021-11-18Added 17 answers

log(57x)=2+log(x2)
log(57x)log(x2)=2
log(57x)x2=2
57xx2=102
(57x)/(x-2)=100
57x=100(x-2)
57x=100x-200
0=43x-200
200=43x
200/43=x
4.65=x

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