Solve for x using log50=600e^{-0.4x}

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Answer 1

To solve equation
\(50=600e^{-0.4x}\)
\(\frac{50}{600}=e^{-0.4x}\)
taking ln of both sides we get
\(\ln(50/600)=\ln e^{-0.4x}\)
\(\ln0.08=\ln e^{-0.4x}\)
since \(\ln e^x=x\)
\(x=-\frac{(-2.53)}{0.4}\)
\(=6.32\)
Hence x=6.32
Result: x=6.32

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Solve for x using log50=600e^{-0.4x}

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