Find the derivative of the function. y=ln|sec x+tan x|

foass77W 2021-02-19 Answered
Find the derivative of the function. y=ln|secx+tanx|
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Expert Answer

Roosevelt Houghton
Answered 2021-02-20 Author has 106 answers
y=ln|secx+tanx|
dydx=d(ln|secx+tanx|)dx
dydx=1(secx+tanx)dsecx+tanxdx
dydx=1(secx+tanx)(secxtanx+sec2x)
dydx=1(secx+tanx)secx(tanx+secx)
dydx=(secx+tanx)(secx+tanx)secx
dydx=secx
Result
dydx=secx
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