Evaluate the definite integral. \int_{3}^{6}(-5x+6)dx

Lorenzolaji

Lorenzolaji

Answered question

2021-11-18

Evaluate the definite integral.
36(5x+6)dx

Answer & Explanation

Ryan Willis

Ryan Willis

Beginner2021-11-19Added 15 answers

Step 1
To evaluate the given definite integral.
Step 2
Given that:
36(5x+6)dx
=5|{3}6xdx+6|36dx
=5[x22]36+6[x]36
=52[6232]+6[63]
=52(369)+6(3)
=52(27)+18
=1352+18
=135+362
=992
36(5x+6)dx=992
menerkupvd

menerkupvd

Beginner2021-11-20Added 12 answers

Step 1: If f(x) is a continuous function from a to b, and if F(x) is its integral, then:
abf(x)dx=F(x)ab=F(b)F(a)
Step 2: In this case, f(x)=(−5x+6). Find its integral.
5x22+6x36
Step 3: Since F(x)ab=F(b)F(a), expand the above into F(6)-F(3):
(5×622+6×6)(5×322+6×3)
Step 4: Simplify.
992

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?