Interest centers around the life of a concrete mixer. Let A be the eve

ffortunyu

ffortunyu

Answered question

2021-11-16

Interest centers around the life of a concrete mixer. Let A be the event that the concrete mixer fails a test, but B be the event that the concrete mixer displays strain wears but does not actually fail. Event A occurs with probability 0.20, and event B occurs with probability 0.35.
a)What is the probability that the concrete mixer does not fail the test?
b)What is the probability that the concrete mixer works perfectly well (i.e., neither displays strain nor fails the test)?
c)What is the probability that the concrete mixer either fails or shows strain in the test?

Answer & Explanation

Momp1989

Momp1989

Beginner2021-11-17Added 21 answers

Step 1
Let, A be event that component tails particular test B be event that compone nt displays strain but does not actually tail.Given, P(A)=0.20P(B)=0.35
Step 2
(a) The probability is:
P(component does not fail test)=1P(component fail test)
=1P(A)
=10.20
=0.80
Step 3
(b) The probability is:
P(component works perfectly)=P(component doest fail test)P(component show strain but nit fail test)
=0.80.35
=0.45
Step 4
(c) The probability is:
P(component either fails or shows strain)=1P[component works perfectly]
=10.45
=0.55
The probability is 0.55.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school probability

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?