Suppose a die is weighted such that the probability of rolling a three

IMLOG10ct

IMLOG10ct

Answered question

2021-11-21

Suppose a die is weighted such that the probability of rolling a three is the same as rolling a six, the probability of rolling a one, two, or four is 3 times that of six, and the probability of rolling a five is 5 times that of rolling a three. Find the probability of 1. rolling a one 2. rolling a two 3. rolling a three 4. rolling a four 5. rolling a five 6. rolling a six

Answer & Explanation

inenge3y

inenge3y

Beginner2021-11-22Added 20 answers

Step 1 
Suppose the likelihood of rolling a six is =x 
Therefore, the likelihood of rolling a three is =x 
the likelihood of getting a one on a die is =3x 
the odds of rolling a two are =3x 
the likelihood of getting a four is =3x 
the likelihood that a five will be rolled is =5x 
Step 2 
We are aware that there is one chance in total.
So, x+x+3x+3x+3x+5x=1 
Or, 16x=1 
Or, x=116 
The likelihood of getting a one on a dice is =3x=3×116=316 
The likelihood of getting a two on a dice is =3x=3×116=316 
The chance of getting a three on the dice is =x=116 
The likelihood of getting a four on the dice is =3x=3×116=316 
The chance of getting a five on the dice is =5x=5×116=516 
The likelihood of getting a six is =x=116 
Answer: 
1) 316 
2) 316 
3) 116 
4) 316 
5) 516 
6) 116

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