Explained: "Solve. x2+15<4x</span> The solution set is.....? (Type your..."

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peromvu

Answered question

2021-11-15

Solve.

x^{2} + 15 < 4 x

</span>
The solution set is.....?
(Type your answer in interval notation. Use integers or fractions for any numbers in the expression. Type an exact answer, using radicals as needed.)

Answer & Explanation

Jick1984

Beginner2021-11-16Added 12 answers

Step 1
Given $x^{2} + 15 < 4 x$
Step 2
Solve for inequality
$x^{2} + 15 < 4 x$
$x^{2} + 15 - 4 x < 4 x - 4 x$
$x^{2} + 15 - 4 x < 0$
$x^{2} - 4 x + 4 + 11 < 0$
${(x - 2)}^{2} + 11 < 0$
${(x - 2)}^{2} + 11 - 11 < - 11$
${(x - 2)}^{2} < - 11$
$\frac{1}{11} {(x - 2)}^{2} < \frac{- 11}{11}$
$\frac{1}{11} {(x - 2)}^{2} < - 1$
no solution exist
Step 3
Therefore, no solution exists.

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