The three balls each weigh 0.5 lb and have a coefficient of restitution of e = 0

Jason Watson

Jason Watson

Answered question

2021-11-18

The three balls each weigh 0.5 lb and have a coefficient of restitution of e = 0.85. If ball A is released from rest and strikes ball B and then ball B strikes ball C, determine the velocity of each ball after the second collision has occurred. The balls slide without friction.

Answer & Explanation

Sharolyn Larson

Sharolyn Larson

Beginner2021-11-19Added 12 answers

T1+V1=T2+V2
T1=12mA(vA)02=12(0.532.2)(0)2=0
V1=mAgh0=0.5×3=1.5lb. fts2
T2=12ma(vA)12=12(0.532.2)(vA)12=7.764×103(vA)12
V2=mAgh1=0.5×0=0
0+1.5=7.764×103(vA)12+0
(vA)1=13.89 fts

(+)mA(vA)1+mB(vB)1=mA(vA)2+mB(vB)2
(0.532.2)(13.89)+(0.532.2)(0)=(0.532.2)(vA)2+(0.532.2)(vB)2
0.2157=0.01553(vA)2+0.01553(vB)2
13.89=(vA)2+(vB)2
(vA)=13.89(vB)2(1)
e=(vB)2(vA)2(vA)1(vB)1
 

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