10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determi

rastafarral6 2021-11-14 Answered

10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

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Expert Answer

Troy Lesure
Answered 2021-11-15 Author has 26 answers

Step 1
First, we calculate the total specific volume of the mixture:
αt=Vm
=0.014m310kg
=0.0014m3kg
Next, we look at table A-12 to determine the values of the specific volumes of the liquid and gas parts and their enthalpies. Since we don't have values for 300 kPa, we have to interpolate from the values for 280 and 320 kPa. Now, we calculate the quality:
q1=αtotαliqαvapαliq
=(0.00140.0007734)m3kg(0.06805750.0007734)m3kg
=0.009
The enthalpy is calculated from the values given in the table A-13, again using interpolations:
h1=hliq+q1hevap
=52.65kJkg+0.009198.195kJkg
=54.43kJkg
The temperature is determined from the given table values also using interpolation:
T1=0.61C
The temperature at 600 kPa, determined from A-12, is:
T2=21.55C
Step 2
The quality of the mixture this pressure is:
q1=αtotαliqαvapαliq
(0.00140.0008198)m3kg(0.0343350.0008198)m3kg
=0.017
The final enthalpy is:
h2=hliq+q2hevap
=81.5kJkg+0.017180.95kJkg
=84.58kJkg
Result
T1=0.61C,h1=54.43kJkg
T2=21.55C,h2=84.58kJkg

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