Solve for Vt begin{bmatrix}20 & -20 &0&0&0 -20 & 41&-18&0&-3 0 &-18&28&-6&-4 0&0&-6&85&-2 0&-3&-4&-2&23 end{bmatrix}begin{bmatrix}i_t i_1 i_2 i_3 i_4 end{bmatrix}=begin{bmatrix}v_t 0 0 0 0 end{bmatrix}

Wotzdorfg 2020-11-24 Answered
Solve for Vt
[2020000204118030182864006852034223][iti1i2i3i4]=[vt0000]
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Expert Answer

StrycharzT
Answered 2020-11-25 Author has 102 answers
Step 1
In linear algebra, matrix multiplication is a binary operation that produces a matrix from two matrices. For matrix multiplication, the number of columns in the first matrix must be equal to the number of rows in the second matrix. The resulting matrix, known as the matrix product, has the number of rows of the first and the number of columns of the second matrix. The product of matrices A and B is then denoted simply as AB.
Step 2
[2020000204118030182864006852034223][iti1i2i3i4]=[vt0000]
20it20i1=vt
20it+41it18i23i4=0
18i1+28i26i34i4=0
6i2+85i32i4=0
3i14i22i3+23i4=0
Let i3=m,i4=n
18i1+28i2=6m+4n
3i14i2=2m23n
solving above two equations we get
i1=157n20m39,i2=71n3m26
it=4120157n20m39182071n3m26320n
So, vt=20(4120157n20m39182071n3m26320n157n20m39)
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Jeffrey Jordon
Answered 2022-01-24 Author has 2064 answers

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