Find the determinants in Exercise , assuming that begin{vmatrix}a & b &c d&e&fg&h&i end{vmatrix}=4 begin{vmatrix}2a & 2b &2c d&e&fg&h&i end{vmatrix}

asked 2020-12-07
Find the determinants in Exercise , assuming that
\(\begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}=4\)
\(\begin{vmatrix}2a & 2b &2c \\ d&e&f\\g&h&i \end{vmatrix}\)

Answers (1)

Step 1
Determinant is used for solving linear equations. To find the inverse of a matrix determinant is used. It is computed only for square matrices. Square matrices are matrices whose number of rows and number of columns are equal.
Step 2
The given value of the determinant is \(\begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}=4\) Multiplying any row or column of a determinant by a number x, multiplies the determinant by that number x. Using this property the value of the determinant \(\begin{vmatrix}2a & 2b &2c \\ d&e&f\\g&h&i \end{vmatrix}\) is calculated by taking the common term 2 from the first row and take the value 2 outside of the determinant, then it becomes 2 times of the determinant \(\begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}\) , using the value given value find the asked determinant value as follows,
\(\begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}=4\)
\(\begin{vmatrix}2a & 2b &2c \\ d&e&f\\g&h&i \end{vmatrix}=\begin{vmatrix}2 \times a & 2 \times b &2 \times c \\ d & e & f \\ g & h &i \end{vmatrix}\)
\(=2\begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}\) Take the coomon term from first row outside of determinant. \(= 2 \times 4 \dotsc \text{ Subtitute } \begin{vmatrix}a & b &c \\ d&e&f\\g&h&i \end{vmatrix}=4\)
\(= 8\)
Hence, the value of the determinant asked in the question is equal to
\(\begin{vmatrix}2a & 2b &2c \\ d&e&f\\g&h&i \end{vmatrix} = 8\)
Best answer

expert advice

Have a similar question?
We can deal with it in 3 hours