To factor the expression 3x^{3}-4x^{2}+6-8 completely.

Pretoto4o 2021-11-17 Answered
To factor the expression
$3{x}^{3}-4{x}^{2}+6-8$
completely.
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Expert Answer

Liek1993
Answered 2021-11-18 Author has 13 answers
Step 1
The given expression is $3{x}^{3}-4{x}^{2}+6x-8$
Make two groups of the terms as shown below L
$\left(3{x}^{3}-4{x}^{2}\right)+\left(6x-8\right)$
Now, factor out the greatest common factor from both the groups.
${x}^{2}\left(3x-4\right)+2\left(3x-4\right)$
Now, factor out $\left(3x-4\right)$ from both the terms.
$\left(3x-4\right)\left({x}^{2}+2\right)$
Now, the two terms in multiplication cannot be factored further.
The factored form of the given expression is $\left(3x-4\right)\left({x}^{2}+2\right)$
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