completely.

Pretoto4o
2021-11-17
Answered

To factor the expression

$3{x}^{3}-4{x}^{2}+6-8$

completely.

completely.

You can still ask an expert for help

Liek1993

Answered 2021-11-18
Author has **13** answers

Step 1

The given expression is$3{x}^{3}-4{x}^{2}+6x-8$

Make two groups of the terms as shown below L

$(3{x}^{3}-4{x}^{2})+(6x-8)$

Now, factor out the greatest common factor from both the groups.

${x}^{2}(3x-4)+2(3x-4)$

Now, factor out$(3x-4)$ from both the terms.

$(3x-4)({x}^{2}+2)$

Now, the two terms in multiplication cannot be factored further.

The factored form of the given expression is$(3x-4)({x}^{2}+2)$

The given expression is

Make two groups of the terms as shown below L

Now, factor out the greatest common factor from both the groups.

Now, factor out

Now, the two terms in multiplication cannot be factored further.

The factored form of the given expression is

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Simplify, please.

$8\left\{[4\left(p\u20134\right)+19]\u2013[2\left(3p\u20132\right)+5]\right\}$

If$8\left\{[4\left(p\u20134\right)+19]\u2013[2\left(3p\u20132\right)+5]\right\}=-16p+16$

If