Given B=begin{bmatrix}-3 & -3 1 & -2 end{bmatrix} text{ and } C=begin{bmatrix}-15 & -6 1 & 10 end{bmatrix} Solve 3X+B=C X=?

ddaeeric 2020-11-27 Answered
Given B=[3312] and C=[156110]
Solve 3X+B=C
X=?
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Expert Answer

Willie
Answered 2020-11-28 Author has 95 answers
Step 1
Given :
The matrices
B=[3312] and C=[156110]
To solve :
The matrix 3 X + B = C for X
Step 2
Given :
The matrices B=[3312] and C=[156110]
Let X=[abcd] then 3X=[3a3b3c3d]
3X+B=C
[3a3b3c3d]+[3312]=[156110]
[3a33b33c+13d2]=[156110]
Equating each element of the matrix , we have
3a3=15
3a=15+3
3a=12
a=123
a=4
3b3=6
3b=6+3
3b=3
b=1
3c+1=1
3c=11
3c=0
c=0
3d2=10
3d=10+2
3d=12
d=123
d=4
Therefore,
X=[4104]
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