If A is diagonalizable and for all eigenvalues , lambda text{ of } A , |lambda|=1 , then A is unitary. True or False?

BenoguigoliB

BenoguigoliB

Answered question

2021-01-04

If A is diagonalizable and for all eigenvalues , λ of A,|λ|=1 , then A is unitary. True or False?

Answer & Explanation

FieniChoonin

FieniChoonin

Skilled2021-01-05Added 102 answers

Step 1
Solution.
Given: A is diagonalizable and all eigenvalue λ of A,|λ|=1
Step 2
Let A=[1101] , the eigenvalue of A is 1,-1 we know that if A has distinct eigenvalue then A is diagonalizable.
A is diagonalizable , and 1,-1 is eigenvalue of A also |1|=1,|1|=1
Now check A is unitary?
If A is unitary then AAT=I ,
AAT=[1101][1101]T=[1101][1011]=[2111][1001]
A is not unitary
Hence if A is diagonalizable and all eigenvalue
λ of A,|λ|=1
then A need not be unitary
The given statement is False
Jeffrey Jordon

Jeffrey Jordon

Expert2022-01-23Added 2605 answers

Answer is given below (on video)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?