Determine the longest interval in which the given initial value

verskalksv 2021-11-15 Answered
Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution. Do not attempt to find the slotuion.
(x2)y+y+(x2)(tanx)y=0
y(3)=1
y(3)=6
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Expert Answer

Marian Tucker
Answered 2021-11-16 Author has 15 answers
The given IVP
(x2)y+y+(x2)(tanx)y=0
y+1x2y+(tanx)y=0
And the initial condition.y(3)=1, y(3)=6
Here P(x)=1x2
q(x)=tanx
g(x)=0 constant function is continuous everywhere.
Solution: ((2n+1)π2,(2n+3)π2)
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