Let F(x,y,z)=xi+yj+zk. Evaluate the integral of F alomg each of

villane0

villane0

Answered question

2021-11-12

Let F(x,y,z)=ξ+yj+zk. Evaluate the integral of F alomg each of the following paths.
c(t)=(t,t,t), 0t3

Answer & Explanation

Heack1991

Heack1991

Beginner2021-11-13Added 13 answers

The given path is c(t)=(t,t,t), 0t3
Obtain the value of line integral of F as follows:
Cds=03F(t,t,t)dcdtdt
=03(t,t,t)(1,1,1)dt
=033tdt
3(t22)03
=3(920)
=272
Thus, the value of line integral of F is 272

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