Find the derivative.y(x) = x \tanh^{−1}(x) + \ln (\sqrt {1-x^2})

trainart1

trainart1

Answered question

2021-11-12

Find the derivative.
y(x)=xtanh1(x)+ln(1x2)

Answer & Explanation

Donald Valley

Donald Valley

Beginner2021-11-13Added 10 answers

Given function is
y(x)=xtanh1(x)+ln(1x2)
we have to difference the function.
So taking differentiation on both sides, we get
y(x)=ddx[xtanh1(x)+ln(1x)]
=ddx[xtanh1(x)]+12ddx[ln(1x2)]
=tanh1(x)+xddx[tanh1(x)]+122x(1x2)
=tanh1(x)+x1x2x1x2
=tanh1(x)
Therefore y(x)=tanh1(x)

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