"Suppose you have a 9.00-V battery, a 2.00..." was answered by our experts

vousetmoiec

Answered question

2021-11-11

Suppose you have a 9.00-V battery, a 2.00 -

μ F

capacitor, and a

7.40 - μ F

capacitor. (a) Find the charge and energy stored if the capacitors are connected to the battery in series

Coldst

Beginner2021-11-12Added 18 answers

Identify the unknown:
The charge and energy stored if the capacitors are connected in series
Set Up the Problem:
Capacitance of a serie combination:

\frac{1}{C_{S}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}} + \dots

\frac{1}{C_{S}} = \frac{1}{2} + \frac{1}{7.4}

C_{S} = \frac{2 \times 7.4}{2 + 7.4} = 1.575 μ F = 1.575 \times 10^{- 6} F

Capacitance of a series combitation is given by:

C_{S} = \frac{Q}{V}

Then the charges stored in the series combination is:

Q = C_{S} V

Energy stored in the series combination is:

U_{C} = \frac{1}{2} V^{2} C_{S}

Solve the problem:

Q = 1.575 \times 10^{- 6} \times 9 = 1.42 \times 10^{- 5} C

U_{C} = \frac{1}{2} \times {(9)}^{2} \times 1.575 \times 1)^{- 6} = 6.38 \times 10^{- 5}

Do you have a similar question?

Recalculate according to your conditions!

Didn't find what you were looking for?