Simplify the following matrices , then find the multiplication AB A=begin{bmatrix}4i & sqrt{-1} sqrt{2}e^{ipi/4} & 5sin(53.13) sqrt{-9} & sqrt{1} end{bmatrix} and B=begin{bmatrix}ln e^3& log_{x}{x^2}& sqrt{-1}ln e^i i log_{y}{y^{2i}} & 2e^{ipi} & ln e^i end{bmatrix}

nicekikah 2021-01-02 Answered
Simplify the following matrices , then find the multiplication AB
A=[4i12eiπ/45sin(53.13)91] and B=[lne3logxx21lneiilogyy2i2eiπlnei]
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Expert Answer

delilnaT
Answered 2021-01-03 Author has 94 answers
Step 1
We have given two matrices,
A=[4i12eiπ/45sin(53.13)91] and B=[lne3logxx21lneiilogyy2i2eiπlnei]
These matrices will be simplified by some formulas:
i2=1
eiaπ=(1)a
And in a right angled triagle ,
sin(53.13)=0.8
So 5sin(53.13)=4
Logarithmic formulas
lnea=a
logaxb=blogax
logxx=1
Step 2
So for the matrix A,
A=[4i12eiπ/45sin(53.13)91]
A=[4ii22(1)1/449i21]
A=[4ii2i43i1] For matrix B
B=[lne3logxx21lneiilogyy2i2eiπlnei]
B=[32iii2i2(1)i]
B=[3212i22i]
B=[32i222i]
Step 3
Now we multiply both the matrices,
AB=[4ii2i43i1][32i222i]
AB=[12i2i8i2i4i+i232i822i82i+4i9i26i23i+i]
AB=[10i6i4i+i232i822i82i+4i9i26i22i]
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Jeffrey Jordon
Answered 2022-01-23 Author has 2070 answers

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