Evaluate the given integral. \int_{0}^{2}(3x^{3}-2x+5)dx

vadulgattp

vadulgattp

Answered question

2021-11-07

Evaluate the given integral.
02(3x32x+5)dx

Answer & Explanation

Howell

Howell

Beginner2021-11-08Added 11 answers

Step 1
Consider the given integral,
I=02(3x32x+5)dx
use the following formula of the integration,
xndx=xn+1n+1
Step 2
using the above formula,
I=[(3x44)2(x22)+5(x)]02
=[(3(2)44)2((2)22)+5((2)){(3(0)44)2((0)22)+5(0)}]
=[12-4+10]
=18
hence the value of the integral is 18.

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