Steam is lo be condensed on the shell side of a heat exchanger at 75^{\circ}F

shadsiei

shadsiei

Answered question

2021-11-10

Steam is lo be condensed on the shell side of a heat exchanger at 75F. Cooling water enters the tubes at 50F at a rate of 43 lbm/s and leaves at 65F. Assuming the heat exhanger to be well-insulated, determine the rate of heat transfer in the heat exchanger and the rate of condensation of the steam.

Answer & Explanation

Jozlyn

Jozlyn

Skilled2021-11-11Added 85 answers

The rate form of the energy balance for this system with steady-state flow is
EEout=Esystem 
we have 
E=Eout 
therefore 
Q+mh1=mh2 
we have 
Q=mcp(T2T1) 
When this happens, the heat exchanger's rate of heat transfer to the cold water becomes
Q=[mcp(ToutT)]H2O 
we replace the values in the equation 
Q=(451lbms)(1.0BtulbmF)(65C50C)Q=675Btus 
the rate of condensation of the steam in the heat exchanger is determined from solve for msteam 
Q=(mhfg)steam 
we replace the values in the equation 
msteam+675Btus1050.9Btulbmmsteam=0.642lbms

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