Calculation:

Given watts beign used by circuit is 1058 i.e. \(\displaystyle{W}={1058}\)

Resistance of the circuit is 2 ohms i.e. \(\displaystyle{R}={2}\)

Plugging the value in the expression:

\(\displaystyle{I}=\sqrt{{{\frac{{{W}}}{{{R}}}}}}\)

\(\displaystyle{I}=\sqrt{{{\frac{{{1058}}}{{{2}}}}}}\)

\(\displaystyle{I}=\sqrt{{{529}}}\)

\(\displaystyle{I}=\sqrt{{{23}^{{{2}}}}}\)

\(\displaystyle{I}={23}\)

Therefore the current in the circuit is 23 amperes.

Given watts beign used by circuit is 1058 i.e. \(\displaystyle{W}={1058}\)

Resistance of the circuit is 2 ohms i.e. \(\displaystyle{R}={2}\)

Plugging the value in the expression:

\(\displaystyle{I}=\sqrt{{{\frac{{{W}}}{{{R}}}}}}\)

\(\displaystyle{I}=\sqrt{{{\frac{{{1058}}}{{{2}}}}}}\)

\(\displaystyle{I}=\sqrt{{{529}}}\)

\(\displaystyle{I}=\sqrt{{{23}^{{{2}}}}}\)

\(\displaystyle{I}={23}\)

Therefore the current in the circuit is 23 amperes.