To calculate the expression 3x(x^{2}+1)^{\frac{1}{2}}(2x^{2}-x)+2(x^{2}+1)^{\

floymdiT

floymdiT

Answered question

2021-11-10

To calculate the expression 3x(x2+1)12(2x2x)+2(x2+1)23(4x1)

Answer & Explanation

Pohanginah

Pohanginah

Skilled2021-11-11Added 96 answers

Calculation:
Given 3x(x2+1)12(2x2x)+2(x2+1)23(4x1)
This can be written as
3x(x2+1)12(2x2x)+2(x2+1)32(4x1)=3x(x2+1)12(2x2x)+2(x2+1)12(x2+1)(4x1)
Factoring out the common terms,
3x(x2+1)12(2x2x)+2(x2+1)32(4x1)
=(x2+1)12(3x(2x2x)+2(x2+1)(4x1))
3x(x2+1)12(2x2x)+2(x2+1)32(4x1)
=(x2+1)12(3x2x23xx+2x24x2x21+214x211)
3x(x2+1)12(2x2x)+2(x2+1)32(4x1)

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