Let A,B,C be n times n matrices. If B=CAC^{-1} show that det(A)=det(B)

Ava-May Nelson

Ava-May Nelson

Answered question

2020-11-09

Let A,B,C be n×n matrices. If B=CAC1 show that det(A)=det(B)

Answer & Explanation

diskusje5

diskusje5

Skilled2020-11-10Added 82 answers

Step 1
Consider that A, B, C are n×n matrices.
Given: B=CAC1
To Show: det(A)=det(B)
Apply property of determinants which says if A1,A2,A3, …An are n×n matrices. Then det(A1A2A3An)=det(A1)det(A2)det(A3)det(An). Therefore
det(B)=det(CAC1)
=det(C)det(A)det(C1)
Step 2
Apply commutative laws of determinants that is, det(A1)det(A2)=det(A2)det(A1).
det(B)=det(CAC1)
=det(C)det(A)det(C1)
=det(C)det(C1)det(A)
Apply property of determinants that det(A11)=1det(A1)
det(B)=det(CAC1)
=det(C)det(A)det(C1)
=det(C)det(C1)det(A)
=det(C)1det(C)det(A)
=det(A)
Jeffrey Jordon

Jeffrey Jordon

Expert2022-01-22Added 2605 answers

Answer is given below (on video)

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