Find the limits: \lim_{x\to\infty}\sqrt{\frac{8x^2-3}{2x^2+x}}

alesterp 2021-11-10 Answered
Find the limits:
limx8x232x2+x
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Expert Answer

FieniChoonin
Answered 2021-11-11 Author has 102 answers
Given:
Consider rational function inside the radical. The highest power of x in the denominator is 2.
So divide numerator and denominator by x^2,
limx8x232x2+x=limx8x2x23x22x2x2+xx2
=limx83x22+1x
Use the limit laws,
limx8x232x2+x=limx(83x2)(2+1x)
=limx(83x2)limx(2+1x)
=802+0
=4
=2
Therefore, limx8x232x2+x=2
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Jeffrey Jordon
Answered 2022-06-26 Author has 2262 answers

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