When finding the nth term in an arithmetic sequence, how do I solve a sequence w

texelaare

texelaare

Answered question

2021-11-10

When finding the nth term in an arithmetic sequence, how do I solve a sequence with fractions? For example {445, 135, 135, 445} When 445 is the 4th term what would the seventh term be and why is the final answer 725?

Answer & Explanation

Cullen

Cullen

Skilled2021-11-11Added 89 answers

Step 1
To justify that the seventh term of the given arithmetic sequence is 725 (given)
Step 2
To start with, an arithmetic sequence is a sequence of the form {a, a+d, a+2d,}, where a and d are any numbers (integers, fractions, real numbers, positive, negative). There is no restriction on the type of numbers a and d.
Step 3
All the standard formulae hold for an arithmetic sequence even if the terms are fractions. (a is the first term and d is the common difference with the usual notation)
Given an arithmetic sequence (of any type of numbers) {a, a+d, a+2d,}
nth term=a+(n1)d
Step 4
The first term a and the common difference d are identified
Given the sequence
{445, 135, 135, 445,} same as
{245, 85, 85, 245,}
We see that this is an arithmetic sequence with a=245 and d=165
Step 5
We can determine the 7th term either directly or using the formula for the nth term. First we find the 7th term directly
{245, 85, 85, 245,}
5th term=245+165=8
\(\displaystyle\text{6th term=8+\frac{16}{\left\lbrace{5}\right\rbrace}={\frac{{{56}}}{{{5}}}}\)
7th term=565+165=725 (as given)
Step 6
ANSWER: Finding the 7th term using the formula for the nth term
{245, 85, 85, 245,}
a=245, d=165;
ntn term=a+(n1)d
So, 7th term=245+6×165
=24+965
=725 (as required)

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