Evaluate the definite integral. \int_{1}^{9}\frac{1}{\sqrt{x}(1+\sqrt{x})^{2}}dx

Khaleesi Herbert

Khaleesi Herbert

Answered question

2021-11-08

Evaluate the definite integral.
191x(1+x)2dx

Answer & Explanation

faldduE

faldduE

Skilled2021-11-09Added 109 answers

Step 1
Given integral
191x(1+x)2dx
Step 2
On solving
191x(1+x)2dx
put 1+x=t12xdx=dt1xdx=2dt
Also, limits are
at x=1,t=1+1=2
at x=9,t=1+9=1+3=4
2241t2dt=2[t2+12+1]24
=2[1t]24
=2[1412]
=12

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