Evaluate the integral without using tables. \int_{0}^{1}(-\ln x)dx

Kyran Hudson

Kyran Hudson

Answered question

2021-11-09

Evaluate the integral without using tables.
01(lnx)dx

Answer & Explanation

diskusje5

diskusje5

Skilled2021-11-10Added 82 answers

Evaluate the integrals as follows:
Substitute u=lnx,du=1xdx,v=1,v=x  udv=uvvdu.
01ln(x)dx=01ln(x)dx
=[xln(x)1dx]01
=[xln(x)x]01
=1

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