waigaK
2021-11-08
Answered

Replace the polar equations with equivalent
Cartesian equations. Then describe or identify the graph. ${r}^{2}=-6r\mathrm{sin}\theta$

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Brighton

Answered 2021-11-09
Author has **103** answers

The Cartesian equation is

Now its the form of of

Hence it represents a circle with centre at (h,k)(0,-3)& radius 3

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Use the given graph off over the interval (0, 6) to find the following.

a) The open intervals on whichfis increasing. (Enter your answer using interval notation.)

b) The open intervals on whichfis decreasing. (Enter your answer using interval notation.)

c) The open intervals on whichfis concave upward. (Enter your answer using interval notation.)

d) The open intervals on whichfis concave downward. (Enter your answer using interval notation.)

e) The coordinates of the point of inflection.$(x,\text{}y)=$

a) The open intervals on whichfis increasing. (Enter your answer using interval notation.)

b) The open intervals on whichfis decreasing. (Enter your answer using interval notation.)

c) The open intervals on whichfis concave upward. (Enter your answer using interval notation.)

d) The open intervals on whichfis concave downward. (Enter your answer using interval notation.)

e) The coordinates of the point of inflection.

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What is (-2, 9) in polar coordinates?

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Vector-valued functions Find a function r(t) that describes the following curve.

A circle of radius 3 centered at (2, 1, 0) that lies in the plane y=1

A circle of radius 3 centered at (2, 1, 0) that lies in the plane y=1

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What is the polar form of (42, 77)?

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Find the domain of the vector-valued function

$r\left(t\right)=\frac{1}{t+1}i+\frac{t}{2}j-3tk$

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Find the area of the region that lies inside both curves. $r=\sqrt{3}\mathrm{cos}\theta ,r=\mathrm{sin}\theta$

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Find all values of x such that the tangent line to $f\left(x\right)={\left({x}^{2}\u20139\right)}^{2}$ is horizontal.