A pair of honest dice is rolled once. Find the expected value of the sum of the

Harlen Pritchard

Harlen Pritchard

Answered question

2021-10-17

A pair of honest dice is rolled once. Find the expected value of the sum of the two numbers rolled.

Answer & Explanation

Gennenzip

Gennenzip

Skilled2021-10-18Added 96 answers

Below is sample space for sum of pair of dice:
S={2,3,4,5,6,7,8,9,10,11,12}
Evaluating probability of each event:
SumProbability21/3632/3643/3654/3665/3676/36
We know Expected value (E) is given by:
E=(p1x1)+(p2x2)+(p3x3)++(pNxN)
Evaluating expected value (E) of the sum of the two numbers rolled:
E=(2136)+(3236)+(4336)+(5436)+(6536)+(7636)
=2+6+12+20+30+42+40+36+30+22+1236
=25236
=7

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