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Geometric series: ∑n=0∞a⋅rn=a1−r Where r and a are constants If |r|<1, then the series converges to a1−r 10−2+0.4−0.08… 10+10⋅(−15)+10⋅(−15)2+10⋅(−15)3… ∑n=0∞10⋅(−15)n This is a geometric series with common ration r=−15 and Initial Term a=10 Since |r|=15<1, the given geometric series converges. Sum of the geometric series is S=a1−r=101−(−15)=101+15=1065=506=253 The series converges to 253
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