Given a right triangle, where one cathetus is $\stackrel{\u2015}{A}=11$ m, the hypothenuse is $\stackrel{\u2015}{C}=15$ m, and $\mathrm{\angle}c={90}^{\circ}$ . Find all missing sides $\left(\stackrel{\u2015}{B}\right){\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\mathrm{\angle}s\left(\mathrm{\angle}a{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}\mathrm{\angle}b\right)$ .