Evaluate the definite integral.\int_{-1}^{1}(ti+t^{3}j+\sqrt[3]{t}k)dt

BolkowN

BolkowN

Answered question

2021-10-24

Evaluate the definite integral.
11(ti+t3j+t3k)dt

Answer & Explanation

broliY

broliY

Skilled2021-10-25Added 97 answers

Step 1
the given integral is:
11(ti+t3j+t3k)dt
Step 2
therefore,
11(ti+t3j+t3k)dt=11(ti+t3j+t13k)dt
=(t22i+t44j+t4343k)11
=(t22i+t44j+34t43k)11
=(12i+14j+34k)(12i+14j+34k)
=0i+0j+0k
=0
therefore, the value of the given definite integral is 0.

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