Given:

\(\begin{array}{c|cc} & \text { Four-wheel drive} & \text { No four-wheel drive } \\\hline \text { Ford } & 28 & 17 \\ \text { Chevy } & 32 & 18 \\ \text { Dodge } & 20 & 10 \end{array}\)

Let us first determine the row/column totals, which is the sum of all counts in the row/column.

\(\begin{array}{c|cc|c} & \text { Four-wheel drive} & \text { No four-wheel drive }&\text{Total} \\\hline \text { Ford } & 28 & 17 &28+17=45 \\ \text { Chevy } & 32 & 18 & 32+18=50\\ \text { Dodge } & 20 & 10 & 20+10=30\\ \hline \text{Total}&28+32+20=80&17+18+10=45& 45+50+30=125 \end{array}\)

The table contains 125 people in total, which is given in the bottom right corner of the table.

The people who own a dodge or have four-wheel drive are given in the row "Dodge” and given in the column ”Four-wheel drive” of the above table, which corresponds with 28+ 32+ 20+ 10= 90 people.

Thus 90 of the 125 people own a dodge or have four-wheel drive.

The probability is the number of favorable outcomes divided by the number of possible outcomes:

\(P(\text{ Dodge or four-wheel drive})=\frac{\text{# of favorable outcomes}}{\text{# of possible outcomes}}=\frac{90}{125}\)

Answer: (d) \(\frac{90}{125}\)