# Use the precise of a limit to prove the following limits. \lim_{x\to3}(-2

Use the precise of a limit to prove the following limits.
$\underset{x\to 3}{lim}\left(-2x+8\right)=2$
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Jozlyn
Given
$\underset{x\to 3}{lim}\left(-2x+8\right)$
$=\underset{x\to 3}{lim}\left(-2x+8\right)$
$=\left(-2\left(3\right)+8\right)$
$=-6+8$
$=2$