Evaluate the following integral. \int_{0}^{2}\int_{x^{2}}^{2x}xy dy dx

ediculeN 2021-10-25 Answered
Evaluate the following integral.
02x22xxydydx
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Expert Answer

cheekabooy
Answered 2021-10-26 Author has 83 answers
Step 1:To determine
Evaluate:
02x22xxydydx
Step 2:Calculation
Consider 02x22xxydydx
=02xy22x22xdx
=02x2((2x)2(x2)2)dx
=02x2(4x2x4)dx
=1202(4x3x5)dx
=12(4x44x66)02
=12(x4x66)02
=12(242660+0)
=12(16646)
=12(96646)
=12(326)
=166
=83
Hence, 02x22xxydydx=83
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