Calculate the integral. int_{-a}^{1}(x^{2}+x)dx

ddaeeric 2021-10-31 Answered
Calculate the integral.
a1(x2+x)dx
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Expert Answer

SkladanH
Answered 2021-11-01 Author has 80 answers
Given
The given integral a1(x2+x)dx
Property used:
(f(x)±g(x))dx=f(x)dx±g(x)dx
Calculation
a1(x2+x)dx=a1(x2)dx+a1(x)dx
=[x33]a1+[x22]a1
=(133(a)33)+(122(a)22)
=13+a33+12a22
On further simplification,
a1(x2+x)dx=13+a33+12a22
=2+2a3+33a26
=2a33a2+56
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