# The following table gives a two-way classification of all basketball players at a state university who began their college careers between 2004 and 20

The following table gives a two-way classification of all basketball players at a state university who began their college careers between 2004 and 2008, based on gender and whether or not they graduated.
$\begin{array}{|ccc|}\hline & \text{Graduated}& \text{Did not Graduate}\\ \text{Male}& 129& 51\\ \text{Female}& 134& 36\\ \hline\end{array}\phantom{\rule{0ex}{0ex}}$
If one of these players is selected at random, find the following probability.
$P\left(\text{graduated or male}\right)=$ Enter your answer in accordance to the question statement
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Step 1
we have given that the following table of two-way classification of all basketball players at a state university who began their college careers between 2004 and 2008, based on gender and whether or not they graduated.
$\begin{array}{|cccc|}\hline & \text{Graduated}& \text{Did not Graduate}& \text{Total}\\ \text{Male}& 129& 51& 180\\ \text{Female}& 134& 367& 170\\ \text{Total}& 263& 87& 350\\ \hline\end{array}\phantom{\rule{0ex}{0ex}}$ We want to find the probability that randomly selected player is graduated or male $P\left(\text{graduated or male}\right)=?$
Step 2
$P\left(\text{graduated or male}\right)=P\left(\text{graduated}\right)+P\left(\text{Male}\right)-P\left(\text{Graduated and Male}\right)$

$=\left(263/350\right)+\left(180/350\right)-\left(129/350\right)$
$=\frac{314}{350}$ = 0.897143
= 0.8971
The probability that randomly selected player is graduated or male = 0.8971
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