Men and women were surveyed regarding their favorite leisure sport, as shown below. All questions pertain to this two-way frequency table. begin{array}{|c|c|c|}hlinetext{Leisure Sport}&text{Golf}&text{Tennis}&text{Skiing}&text{Total}hlinetext{Men} &32 & 21 & 30&83 hlinetext{Women}& 35 & 30&26&91hline text{Total}&67&51&56&174 hline end{array} text{Find P(men)} cdot text{P(skiing)}. (Choose a numbered choice from the list below.) 1) frac{83}{174} 2) frac{56}{174}4 3) frac{4648}{174} 4) frac{4648}{174^2}

Men and women were surveyed regarding their favorite leisure sport, as shown below. All questions pertain to this two-way frequency table. begin{array}{|c|c|c|}hlinetext{Leisure Sport}&text{Golf}&text{Tennis}&text{Skiing}&text{Total}hlinetext{Men} &32 & 21 & 30&83 hlinetext{Women}& 35 & 30&26&91hline text{Total}&67&51&56&174 hline end{array} text{Find P(men)} cdot text{P(skiing)}. (Choose a numbered choice from the list below.) 1) frac{83}{174} 2) frac{56}{174}4 3) frac{4648}{174} 4) frac{4648}{174^2}

Question
Two-way tables
asked 2021-02-13
Men and women were surveyed regarding their favorite leisure sport, as shown below. All questions pertain to this two-way frequency table.
\(\begin{array}{|c|c|c|}\hline\text{Leisure Sport}&\text{Golf}&\text{Tennis}&\text{Skiing}&\text{Total}\\\hline\text{Men} &32 & 21 & 30&83\\ \hline\text{Women}& 35 & 30&26&91\\\hline \ \text{Total}&67&51&56&174 \\ \hline \end{array}\)
\(\text{Find P(men)} \cdot \text{P(skiing)}.\)
(Choose a numbered choice from the list below.)
\(1) \frac{83}{174}\)
\(2) \frac{56}{174}4\)
\(3) \frac{4648}{174}\)
\(4) \frac{4648}{174^2}\)

Answers (1)

2021-02-14

Step 1
From the table, we see that there are total 83 men.
There are total 174 persons.
So the probability of getting a man \(\text{P(men)}=\frac{83}{174}\) From the table we see that total 56 people are skiing. So the probability of skiing is
\(\text{P(Skiing)}=\frac{56}{174}\)
Step 2
Plugging the probabilities in the given expression we get:
\(\text{P(men)}\cdot\text{P(skiing)}\)
\(=\frac{83}{174} \times \frac{56}{174}\)
\(=\frac{4648}{174^2}\)

Answer: \(4)\frac{4648}{174^2}\)

0

Relevant Questions

asked 2021-06-13
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a) Men
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d) Flag this Question
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Group of answer choices
\(P>0.250\)
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asked 2020-11-26
A random sample of 2,500 people was selected, and the people were asked to give their favorite season. Their responses, along with their age group, are summarized in the two-way table below.
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MPa
State which estimator you used.
\(x\)
\(p?\)
\(\frac{s}{x}\)
\(s\)
\(\tilde{\chi}\)
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MPa
State which estimator you used.
\(s\)
\(x\)
\(p?\)
\(\tilde{\chi}\)
\(\frac{s}{x}\)
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MPa
Interpret this point estimate.
This estimate describes the linearity of the data.
This estimate describes the bias of the data.
This estimate describes the spread of the data.
This estimate describes the center of the data.
Which estimator did you use?
\(\tilde{\chi}\)
\(x\)
\(s\)
\(\frac{s}{x}\)
\(p?\)
d) Calculate a point estimate of the proportion of all such beams whose flexural strength exceeds 10 MPa. [Hint: Think of an observation as a "success" if it exceeds 10.] (Round your answer to three decimal places.)
e) Calculate a point estimate of the population coefficient of variation \(\frac{?}{?}\). (Round your answer to four decimal places.)
State which estimator you used.
\(p?\)
\(\tilde{\chi}\)
\(s\)
\(\frac{s}{x}\)
\(x\)
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Round your answer for the excepted count to one decimal place, and your answer for the contribution to the chi-square statistic to three decimal places.
Expected count=?
contribution to the chi-square statistic=?
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In a General Social Survey of Americans in 1991, two variables, gender and finding life exciting or dull, were measured on 980 individuals. The two-way table below summarizes the results.
Let A = randomly chosen person is female
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(a) Find P(A | B)
(b) Are the events A & B independent?
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asked 2021-01-13
Below is a two-way frequency table. Which of the following frequencies show the proportion of male respondents who are in the chess club?
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\(b)\frac{2}{40}=0.05\)
\(c)\frac{2}{12}\approx0.167\)
\(d)\frac{2}{100}=0.02\)
asked 2021-02-08
This two-way table shows the results of asking students if they prefer to have gym class in the morning or the afternoon A.How many students participate in the survey B. How many students in grade 8 prefer to have gym in the morning C. How many grade 10 students participated in the survey D. How many students prefer To have gym in the afternoon
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