1. Going forward, let’s define as the average number of dots after forty rolls. What is the expected value of x? The standard deviation of x is 2.197. What is the standard error of x? 2. What is the probability of obtaining an average that is less than 4.25? n = 40 sigma= 2.197

BenoguigoliB 2021-02-06 Answered
1. Going forward, let’s define as the average number of dots after forty rolls.
What is the expected value of x?
The standard deviation of x is 2.197. What is the standard error of x?
2. What is the probability of obtaining an average that is less than 4.25?
n=40
σ=2.197
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Expert Answer

SoosteethicU
Answered 2021-02-07 Author has 102 answers
Step 1
Note: For ques 2, mean is not given so we could not find the probability. I have provided the formula. You need to put the mean and find the probability of P(Z<z) using Normal Distrbution table.
Step 2
Expected value of average is given by
E(X)=E(Xin)=1n×n×E(X)=E(X)
V(X)=V(Xin)=1n2×n×V(X)=VXn
Standart error of x is given by
σx=VXn=σxn
σx=2.19740=0.347
Probability of obtaining an average that is less than 4.25
Z-score is given by the following formula
Z=xμσ/n=4.25μ2.197/40
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