Simplify 1)begin{bmatrix}4 & 5 end{bmatrix}+begin{bmatrix}6 & -4 end{bmatrix} 2)begin{bmatrix}4 & -13&3-5&-4 end{bmatrix}-begin{bmatrix}4 & -23&6-5&-6

e1s2kat26

e1s2kat26

Answered question

2021-02-11

Simplify
1)[45]+[64]
2)[413354][423656]
3)[4163]+[5655][2026]
Solve for x and y
[104x1]+[58y10]=[15x1611]

Answer & Explanation

SchepperJ

SchepperJ

Skilled2021-02-12Added 96 answers

Step 1 To solve the given matrices. Step 2 Given that 1)[45]+[64]
[4+654]
[101]
[45]+[64]=[101]
2)[413354][423656]
[441+233365+54+6]=[010302]
[413354][423656]=[010302]
3)[4163]+[5655][2026]
[4+5+21606+5+235+6]
[35132]
[4163]+[5655][2026]=[35132]
Given that
[104x1]+[58y10]=[15x1611]
[1054+8x+y110]=[15x1611]
[154x+y11]=[15x1611]
Equating on both sides we have
x=4
x+y=16
Since x=4 then 4+y=16
y=12
x=4 and y=12

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