The solution of the equations or inequalities and express it in interval notatio

Calculation:
a. Inequality is ${\displaystyle 4<2y\text{or}-3(y+2)\succ 2y+1}$
Solution is given as:
${\displaystyle 4<2y\text{or}-3y-6\succ 2y+1}$
${\displaystyle y>2\text{or}-3y+2y>6+1}$
${\displaystyle y>2\text{or}-y>7}$
${\displaystyle y>2\text{or}y<-7}$
Solution in interval notation form is ${\displaystyle 8,-7?(2,8)}$
b. Inequality is ${\displaystyle 4<2y\text{and}-3(y+2)\succ 2y+1}$
Solution is given as:
${\displaystyle 4<2y\text{and}-3y-6\succ 2y+1}$
${\displaystyle y>2\text{and}-3y+2y>6+1}$
${\displaystyle y>2\text{and}-y>7}$
${\displaystyle y>2\text{and}y<-7}$
Solution in interval notation form is ${\displaystyle 8,-7n(2,8)}$
Conclusion: Hence, the solutions for the below equations and inequalities are as follows:
a. ${\displaystyle 4<2y\text{or}-3(y+2)\succ 2y+1}$:

Solution is ${\displaystyle y<-7\text{or}y>2}$
b. ${\displaystyle 4<2y\text{and}-3(y+2)\succ 2y+1}$:

Solution is ${\displaystyle y\succ 7\text{and}y>2}$